Smallest Common Multiple
How do I make an smallest common multiple?
Find the smallest common multiple of the provided parameters that can be evenly divided by both, as well as by all sequential numbers in the range between these parameters.. What is a smallest common multiple? How do you make a smallest common multiple? This script and codes were developed by Victor Hall on 13 September 2022, Tuesday.
Smallest Common Multiple - Script Codes HTML Codes
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<body> <h1>Explaination<h1> <p>Divide the problem up: you have an array that always has two numbers. You want to turn that into an array from smallest to largest. So given [5, 1], you want to turn that into [1,2,3,4,5]. Then you can find the common multiple. It has to be the largest number or a multiple of it. So in this case, check if every number divides evenly into 5. If it doesn't, check it divided into 5 + 5 (10). If it doesn't, check it divided into 10 + 5 and so on: as soon as you get a number that divides, immediately return; that's the solution.</p>
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This is an issue; there are ways to optimise (there will be various values you can ignore if you calculate things first), but for this level, it just needs to work. You'd do stuff like threading and parallelising the calculations in other languages; JS has a massive disadvantage if you need to do maths stuff (primes, factorising, cryptographic stuff etc, normally you'd use C or Julia or similar)</p> <em>Credited by: Dan Couper - github.com/DanCouper </em> <script src="js/index.js"></script>
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Smallest Common Multiple - Script Codes CSS Codes
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Smallest Common Multiple - Script Codes JS Codes
function smallestCommons(arr) { var largest = 0; var smallest = 0; var combinedArr = []; //this is only used to keep the loop going //I did not want to use a nested for loop var found = false; //finds the smallest and largest number if (arr[0] < arr[1]){ largest = arr[1]; smallest = arr[0]; }else{ smallest = arr[1]; largest = arr[0]; } //this number will be added until we reach the common multiple //that is evenly divisible by all numbers in range var multiple = largest; //Finds all values between both numbers passed in array. for(var i = smallest; i <= largest; i++){ combinedArr.push(i); } while(found !== true){ for (var o = smallest; o <= largest; o++){ //tests all numbers in interval to make sure //they are all evenly divisible if(multiple % o !== 0){ break; } //if it reached the end of the loop that means they are all //evenly divisible if (o === largest){ found = true; return multiple; } }//end of loop multiple = multiple + largest; }
}
smallestCommons([1,13]);
Developer | Victor Hall |
Username | vhall_io |
Uploaded | September 13, 2022 |
Rating | 3 |
Size | 2,702 Kb |
Views | 28,336 |
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